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Object???Oriented Programming with Swift 2

You're reading from  Object???Oriented Programming with Swift 2

Product type Book
Published in Jan 2016
Publisher
ISBN-13 9781785885693
Pages 332 pages
Edition 1st Edition
Languages
Author (1):
Gaston C. Hillar Gaston C. Hillar
Profile icon Gaston C. Hillar

Table of Contents (16) Chapters

Object–Oriented Programming with Swift 2
Credits
About the Author
About the Reviewers
www.PacktPub.com
Preface
1. Objects from the Real World to Playground 2. Structures, Classes, and Instances 3. Encapsulation of Data with Properties 4. Inheritance, Abstraction, and Specialization 5. Contract Programming with Protocols 6. Maximization of Code Reuse with Generic Code 7. Object-Oriented Programming and Functional Programming 8. Extending and Building Object-Oriented Code Exercise Answers Index

Defining subscripts with extensions


Let's consider that we still cannot access the code for the previously declared Point3D class. We are working on an app, and we discover that it would be nice to access the x, y, and z values of a Point3D instance with [0], [1], and [2]. We can easily add a subscript by extending the Point3D class.

The following lines use the extension keyword to a subscript to the existing Point3D class:

extension Point3D {
    public subscript(index: Int) -> Int? {
        switch index {
        case 0: return x
        case 1: return y
        case 2: return z
        default: return nil
        }
    }
}

The following lines use the recently added subscript to access the elements of a Point3D instance:

var point3D7 = Point3D(x: 10, y: 15, z: 4)
if let point3D7X = point3D7[0] {
    print("X or [0]: \(point3D7X)")
}
if let point3D7Y = point3D7[1] {
    print("Y or [1]: \(point3D7Y)")
}
if let point3D7Z = point3D7[2] {
    print("Z or [2]: \(point3D7Z)")
}

The following...

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