Creating a boot-up menu

We shall now apply the methods introduced in the previous scripts and reapply them to create a menu that we can customize to present a range of quick-to-run commands and programs.

How to do it…

Create the menu.py script using the following code:

#!/usr/bin/python3
#menu.py
from subprocess import call

filename="menu.ini"
DESC=0
KEY=1
CMD=2

print ("Start Menu:")
try:
  with open(filename) as f:
    menufile = f.readlines()
except IOError:
  print ("Unable to open %s" % (filename))
for item in menufile:
  line = item.split(',')
  print ("(%s):%s" % (line[KEY],line[DESC]))
#Get user input
running = True
while(running):
  user_input = input()
  #Check input, and execute command
  for item in menufile:
    line = item.split(',')
    if (user_input == line[KEY]):
      print ("Command: " + line[CMD])
      #call the script
      #e.g. call(["ls", "-l"])
      commands = line[CMD].rstrip().split()
      print (commands)
      running = False
      #Only run command is one...