Chapter 2
(2.1)
(a)It is not a qubit state because it is not normalized (1 2+1 2 = 2≠1).
(b)It is a qubit state because 4∕7 + 3∕7 = 1.
(c)It is not a qubit state because 2 2≠1.
(d)It is a qubit state as
2 = 1.
(e)We could take x =
=
∕3.
(f)The values x = (1∕
)ei𝜃 for any real 𝜃.
(2.2)
(a)The probability of obtaining 0 will be 1∕2, and so will the that of obtaining 1.
(b)The measurement will always return 0.
(c)The probability of obtaining 0 is 1∕3. That of obtaining 1 is 2∕3.
(d)The probability of obtaining 0 is p. That of obtaining 1 is 1 − p.
(2.3)
All the probabilities are equal to 1∕2 because
2 =
2 =
2 =
2 = 1∕2.
(2.4)
The conjugate transpose of U1 is U1 itself and a simple verification reveals that U1†U1 = U1U1† = U1U1 is equal to the identity matrix. Regarding the other matrices, we have
The matrices U2 and U3 are unitary, but U4 is not because
which is not equal...